X^2+24x+108=0

Solution for X^2+24x+108=0 equation:

X^2+24X+108=0

a = 1; b = 24; c = +108;
Δ = b2-4ac
Δ = 242-4·1·108
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12}{2*1}=\frac{-36}{2}
=-18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12}{2*1}=\frac{-12}{2}
=-6
$